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A 4.5cm tall object is placed 28cm in front of a spherical mirror. It is to produce a virtual image that is upright and 3.5cm tall.

a) What type of mirror is used ?
b) Where is the image located ?
c) What is the focal length ?
d) What is the radius of curvature ?

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Adarsh321
A- convex B- 21.77cm C- 0.01022cm D- 0.02044cm

Concave mirror has been used to create virtual pictures.

According to Magnification formula;

H1 / H2 = -v / u

3.5 / 4.5 = -v / 28

v = -21.78 cm (Image is virtual)

According to Mirror formula;

1/f = 1/v + 1/u

f = [(-21.78)(28)] / [(-21.78) + (28)]

f = -98.045 cm

Radius of Curvature

Radius of Curvature = 2f

Radius of Curvature = 2(-98.045)

Radius of Curvature = -196.09 cm

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https://brainly.com/question/22714636?referrer=searchResults

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