Respuesta :
No. The right answer is A. notice the rising x and the declining y
The Standard form of [tex]8x^2y^2 - \frac{3x^3y}{2} + 4x^4 - 7xy^3[/tex] will be [tex]-7xy^3 + 8x^2y^2 - \frac{3x^3y}{2} + 4x^4[/tex] .
What is Standard form ?
Standard form means that the terms are ordered from biggest exponent to lowest exponent.
We have,
[tex]8x^2y^2 - \frac{3x^3y}{2} + 4x^4 - 7xy^3[/tex]
To write it in standard form we will first simplify the polynomial and then arrange in standard form.
[tex]8x^2y^2 - \frac{3x^3y}{2} + 4x^4 - 7xy^3[/tex]
Now,
As we see polynomial, [tex]y[/tex] have highest exponent as well as constant term [tex]4x^4[/tex] as it do not have [tex]y[/tex] with it.
So,
Move [tex]-7xy^3[/tex] toward left hand;
[tex]- 7xy^3+8x^2y^2 - \frac{3x^3y}{2} + 4x^4[/tex]
So, the obtained polynomial is the standard form of the given polynomial.
Hence, we can say that the Standard form of [tex]8x^2y^2 - \frac{3x^3y}{2} + 4x^4 - 7xy^3[/tex] will be [tex]-7xy^3 + 8x^2y^2 - \frac{3x^3y}{2} + 4x^4[/tex] .
To know more about standard form click here
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