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Train A and train B leave a central station at the same time. They travel the same speed, but in opposite directions, with train A heading towards station A, and train B heading towards station B. Train A reaches station A after 3 h. Train B reaches station B after 2 1/4 h. Station A and B are 420 mi apart.

What is the rate of the trains?

Respuesta :

merlynthewhizz
Train A:

Distance (s) = 420 miles
Time (t) = 3 hours
Speed (v) = distance ÷ time = 420 ÷ 3 = 140 miles/hour

Train B: 

Distance (s) = 420 miles
Time (t) = 2.25 hours
Speed (v) = distance ÷ time = 420 ÷ 2.25 = 186.7 miles/hour
christianvincentrob

Answer:

80mph

Step-by-step explanation:

you add the time which is 3 and 2 1/4 hours. Then you look at the equation d = r/t. d = distance, r = rate, and t = time. Then you put them in there places like this, 420 = (2 1/4 + 3)/ r. 2 1/4 + 3 = 5.25. Then 420/5.25 to get 80 mph

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