Answer:
The length of each side of the original square was [tex]15[/tex] inches
Step-by-step explanation:
Let
x------> the length side of the original square
we know that
The perimeter of a square is equal to
[tex]P=4b[/tex]
where
b is the length side of the square
In this problem
[tex]b=(x+2.5)\ in[/tex]
[tex]P=70\ in[/tex]
substitute
[tex]70=4(x+2.5)[/tex]
solve for x
[tex]70=4x+10[/tex]
[tex]4x=70-10[/tex]
[tex]x=60/4=15\ in[/tex]
