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Which is the correct net ionic equation for the following reaction: H3PO4 (aq) + 3 LiOH (aq) > Li3PO4 (aq) + 3 H2O (l)?
1.)H3PO4 (aq) + 3 OH_ (aq) >PO4_3 (aq) + 3 H2O (l)
2.)H3PO4 (aq) >PO4_3 (aq) + 3 H2O (l)
3.)3 LiOH (aq) + 3 H+ (aq) >Li+ (aq) + 3 H2O (l)
4.)H3PO4 (aq) + 3 LiOH (aq) >Li3PO4 (aq) + 3 H2O (l)
what is the correct net ionic equation for the following reaction: 2 HBr (aq) + Co(OH)2 (aq) >CoBr2 (aq) + 2 H2O (l)?
1.)2 H+ (aq) + Co(OH)2 (aq) >Co+2 (aq) + 2 H2O (l)
2.)Co(OH)2 (aq) >Co+2 (aq) + OH− (aq)
3.)H+ (aq) + OH− (aq) >H2O (l)
4.)2 HBr (aq) + Co(OH)2 (aq) >CoBr2 (aq)+2H2O(l)

Respuesta :

syed514
1.)H3PO4 (aq) + 3 OH− (aq) > PO4−3 (aq) + 3 H2O (l)
2.)H+ (aq) + OH− (aq) > H2O (l)
hope it helps

Answer: The correct option for the chemical equation [tex]H_3PO_4(aq.)+3LiOH(aq.)\rightarrow Li_3PO_4(aq.)+3H_2O(l)[/tex] is 1.

The correct option for the chemical equation [tex]2HBr(aq.)+Co(OH)_2(aq.)\rightarrow CoBr_2(aq.)+2H_2O(l)[/tex] is 3.

Explanation:

  • For the chemical equation:

[tex]H_3PO_4(aq.)+3LiOH(aq.)\rightarrow Li_3PO_4(aq.)+3H_2O(l)[/tex]

[tex]H_3PO_4[/tex] is a weak acid and hence will not dissociate into ions whereas LiOH is a strong base and will easily dissociate into ions.

The product [tex]Li_3PO_4[/tex] is soluble in water and hence, will dissociate into its respective ions. Hence, the ionic equation for this reaction is:

[tex]H_3PO_4(aq.)+3Li^{3+}(aq.)+3OH^-(aq.)\rightarrow 3Li^{3+}(aq.)+PO_4^{3-}(aq.)+3H_2O(l)[/tex]

Net ionic equation becomes:

[tex]H_3PO_4(aq.)+3OH^-(aq.)\rightarrow PO_4^{3-}(aq.)+3H_2O(l)[/tex]

So, the correct option is 1.

  • For the chemical equation:

[tex]2HBr(aq.)+Co(OH)_2(aq.)\rightarrow CoBr_2(aq.)+2H_2O(l)[/tex]

HBr and [tex]Co(OH)_2[/tex] are strong acid and strong base respectively, hence they will easily dissociate into ions.

The product, [tex]CoBr_2[/tex] is is soluble in water and hence, will dissociate into its respective ions. Hence, the ionic equation for this reaction is:

[tex]2H^+(aq.)+2Br^-(aq.)+Co^{2+}(aq.)+2OH^-(aq.)\rightarrow Co^{2+}(aq.)+2Br^-(aq.)+H_2O(l)[/tex]

The net ionic equation becomes:

[tex]H^+(aq.)+OH^-(aq.)\rightarrow H_2O(l)[/tex]

So, the correct option is 3.

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