Respuesta :
A. return period =1/p
where p= prob x>25
Z=(x-mean)/stand dev,
Recall stand dev = sqrt(variance)
Z=(25-15)/4
Z=2.5 which corresponds to .4938
Prob of x>25=.5-.4938=.0062
p=.0062
1/p = 161.29
161 days
where p= prob x>25
Z=(x-mean)/stand dev,
Recall stand dev = sqrt(variance)
Z=(25-15)/4
Z=2.5 which corresponds to .4938
Prob of x>25=.5-.4938=.0062
p=.0062
1/p = 161.29
161 days
The return period for this center rounded to the nearest day is 161 days.
Calculation of the return period:
Since there is a maximum of 25 students per day. Suppose that the number X of students visiting this center each day is a normal random variable with mean 15 and variance 16.
So, we know that
Z=(x-mean)/stand deviation
Z=(25-15)/4
Z=2.5
= .4938
Now
Prob of x>25=.5-.4938=.0062
p=.0062
1/p = 161.29
Hence, The return period for this center rounded to the nearest day is 161 days.
Learn more about variance here: https://brainly.com/question/24138432