Respuesta :
Correct answer is B.
The area of the right triangle is [tex]A= \frac{ab}{2} [/tex].
In this case we have
[tex]24= \frac{3b \times b}{2} \\24 \times 2=3b^2 \\b^2= \frac{24 \times 2}{3} \\b^2=16 \\b=\pm 4 [/tex]
Since the length of a side cannot be negative, the final result is [tex]b=4[/tex].
The area of the right triangle is [tex]A= \frac{ab}{2} [/tex].
In this case we have
[tex]24= \frac{3b \times b}{2} \\24 \times 2=3b^2 \\b^2= \frac{24 \times 2}{3} \\b^2=16 \\b=\pm 4 [/tex]
Since the length of a side cannot be negative, the final result is [tex]b=4[/tex].
