Answer : The equilibrium constant is, [tex]9.928\times 10^{-2}[/tex]
Solution : Given,
Equilibrium concentration of [tex]NH_3[/tex] = 0.272 M
Equilibrium concentration of [tex]H_2S[/tex] = 0.365 M
The given balanced equilibrium reaction is,
[tex]NH_4HS(s)\rightleftharpoons NH_3(g)+H_2S(g)[/tex]
The expression for equilibrium constant will be,
[tex]K_c=\frac{[NH_3][H_2S]}{[NH_4HS]}[/tex]
Now put all the given values in this formula, we get value of equilibrium constant.
[tex]K_c=\frac{(0.272)\times (0.365)}{1}[/tex]
[tex]K_c=0.09928=9.928\times 10^{-2}[/tex]
Therefore, the equilibrium constant is, [tex]9.928\times 10^{-2}[/tex]
