Answer:
The correct answer is silver nitrate solution that is [tex]AgNO_3(aq)[/tex].
Explanation:
To separate [tex]Br^-[/tex] from [tex]NO_{3}^-[/tex] ions we will use silver nitrate solution. On addition of silver nitrate solution in a mixture of bromide and nitrate ions.
The silver ion will react with bromide ions to form silver bromide which will get precipitated out as yellow color solid from a mixture.
[tex]AgNO_3(aq)+Br^-(aq)\rightarrow AgBr(s)+NO_{3}^-(aq)[/tex]
[tex]AgNO_3(aq)+NO_{3}^-(aq)\rightarrow [/tex] no reaction
