Respuesta :
Explanation:
1) Sodium is an alkali metal which positive sodium ion after losing an electron.
[tex][Na]^{11}=1s^22s^22p^63s^1[/tex]
After losing an electron it will attain stable electronic configuration.
[tex][Na]^+=1s^22s^22p^63s^0[/tex]
Number of protons in sodium ion = 11 protons
All filled energy levels in Sodium ion
2) Neon is noble gas with fully filled outermost valence shell. Inert in nature
[tex][Ne]^{10}=1s^22s^22p^6[/tex]
Number of protons in neon atom = 10 protons
All filled energy levels in Neon atom
3) Fluorine belongs to halogen family. Highly electro-negative element. By gaining one electron it will attain attain form negatively charged ion
[tex][F]^{9}=1s^22s^22p^5[/tex].
By gaining one electron it will attain stable electronic configuration.
[tex][F]^{-}=1s^22s^22p^6[/tex].
Number of protons in fluorine ion = 9 protons
All filled energy levels in fluorine ion
All these ions are isoelectronic species with different number of protons and same number of electrons.
- For isoelectronic species, the atom which has the highest number of protons will strongly hold the electrons and will have the highest ionization enthalphy and will have the smallest size. The atom which has the smallest number of protons will easily loose electrons and will have the lowest ionization enthalpy and have the largest size.
- Order of ionization enthalpy will be
[tex]I.E._{F^-}<I.E._{Ne}<I.E._{Na^+}[/tex]
- Order of radii will be
[tex]Na^+<Ne<F^-[/tex]
