Answer:
The object’s resultant angle of motion with the +x-axis after the collision is 47 .
Step-by-step explanation:
It is given that Object A travels in the +x-direction before hitting a stationary object B. From object A’s x-momentum is [tex]5.7{\times}10^4kgms^{-1}[/tex] and its y-momentum is [tex]6.2{\times}10^4kgms^{-1}[/tex].
We know that tan of the angle from the x-axis is given as:
[tex]tanx=\frac{5.7{\times}10^4}{6.2{\times}10^4}[/tex]
[tex]tanx=\frac{5.7}{6.2}[/tex]
[tex]tanx=1.09[/tex]
[tex]x=tan^{-1}(1.09)[/tex]
[tex]x=47.4[/tex]
Therefore, The object’s resultant angle of motion with the +x-axis after the collision is 47 .
