Respuesta :
Answer with explanation:
Time taken by Molly to prepare the Report = 6 hours
Work done in 1 hour [tex]=\frac{1}{6}[/tex]
Time taken by Jere to prepare the Report = 4 hours
Work done in 1 hour [tex]=\frac{1}{4}[/tex]
Their Combined Work , is given by the equation
[tex]=\frac{1}{6}+\frac{1}{4}\\\\=\frac{6+4}{6\times 4}\\\\=\frac{10}{24}[/tex]
Time it would take for Molly and Jere to prepare a report together is equal to
[tex]=\frac{24}{10}\\\\=2.4[/tex]
= 2.4 hours
Answer:
Total time taken by Molly and Jere to prepare a report together = 2.4 hours
Step-by-step explanation:
Time taken by Molly to prepare a report = 6 hours
[tex]\text{So, one hour work of Molly = }\frac{1}{6}\text{ hours}[/tex]
Time taken by Jere to prepare a report = 4 hours
[tex]\text{So, one hour work of Jere = }\frac{1}{4}\text{ hours}[/tex]
Now, we need to calculate the total time taken by Molly and Jere to prepare a report together.
[tex]\text{Time taken by Molly and Jere to prepare a report together = }\frac{1}{6}+\frac{1}{4}\\\\\implies \frac{6+4}{24}\\\\\implies \frac{10}{24}\\\\\implies \text {Total time taken by Molly and Jere to prepare a report together = }\frac{24}{10} =2.4\text{ hours}[/tex]
Hence, Total time taken by Molly and Jere to prepare a report together = 2.4 hours
