Answer:
The factors of given equation [tex]5x^2+29x-6[/tex] is [tex](5x-1)(x+6)[/tex]
Step-by-step explanation:
Given equation [tex]5x^2+29x-6[/tex]
We have to determine the factors of given equation.
Quadratic equation is an equation with highest degree 2.
Consider the given quadratic equation [tex]5x^2+29x-6[/tex]
We can solve the quadratic equation [tex]5x^2+29x-6[/tex] using middle term splitting method.
splitting middle term can be done by writing middle term in such a way that the product of coefficient is the product of remaining two terms.
29x can be written as 30x-1x
[tex]\Rightarrow 5x^2+29x-6[/tex]
[tex]\Rightarrow 5x^2+30x-x-6[/tex]
Taking 5x common from first two terms and -1 from last two terms , we have,
[tex]\Rightarrow 5x(x+6)-1(x+6)[/tex]
[tex] 5x^2+29x-6=(5x-1)(x+6)[/tex]
Thus, the factors of given equation [tex]5x^2+29x-6[/tex] is [tex](5x-1)(x+6)[/tex]
