A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function
h=-16t^2+36t+10 In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ballÍs maximum height?
h = - 16 t² + 36 t + 10 The maximum height of the ball is at the vertex of the parabola. t = - b / 2 a t = -36/-32 t = 1.12 s The maximum height of the ball: h max = - 16 * 1.12² + 32* 1.12 + 10 = - 16 * 1.2544 + 35.84 + 10 = = - 20.0704 + 45.84 = 25.7696 = 25.77 m
