Respuesta :
This is an example of a perfect inelastic collision. After the collision the two gliders move as one object. Since the system is closed, total momentum is conserved.
P1 = P2P1 = PA1 + PB1, PA1 - momentum of glider A before collision PB1 - momentum of glider B before collisionP1 = (0.40)(4.00) + (0.40)(0.00) = 1.60 kg-m/sP2 = (0.40 + 0.40)(v), v is the final velocity of the two objects1.60 = 0.80v
Therefore, v = 2.00 m/s
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P1 = P2P1 = PA1 + PB1, PA1 - momentum of glider A before collision PB1 - momentum of glider B before collisionP1 = (0.40)(4.00) + (0.40)(0.00) = 1.60 kg-m/sP2 = (0.40 + 0.40)(v), v is the final velocity of the two objects1.60 = 0.80v
Therefore, v = 2.00 m/s
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
