Respuesta :

Azieq
x^2 + ( 2/2 )^2 - ( 2/2 )^2 = y - 9
( x + 1 )^2 = y - 9 + 1
( x + 1 )^2 = y - 8
Vertex = ( - 1 , 8 )

i am a mathematics teacher. if anything to ask please pm me

The vertex of the parabola can be found by expressing its equation into vertex form. This processes uses completing the square.

y = x^2 + 2x + 9y = x^2 + 2x + 1 - 1 + 9y = (x + 1)^2 - 1 + 9y = (x + 1)^2 + 8

Thus, vertex is (-1, 8).

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