Respuesta :
The answer is 1/3
To calculate this will use several rules:
[tex] \sqrt[n]{x^m } = x^{ \frac{m}{n} } [/tex]
[tex]x^{-m}= \frac{1}{ x^{m} } [/tex]
[tex] x^{a} * x^{b} =x ^{a+b} [/tex]
[tex] \frac{ x^{a} }{ x^{b} } = x^{a-b} [/tex]
The fourth root of 9 is [tex] \sqrt[4]{9}= \sqrt[4]{ 9^{1} }= 9^{ \frac{1}{4} } [/tex]
Square root of 9 is [tex] \sqrt[2]{9}= \sqrt[2]{ 9^{1} } = 9^{ \frac{1}{2} } [/tex]
The fourth root of 9 to the power of 5 is [tex] \sqrt[4]{9^{5} } = 9^{ \frac{5}{4} } [/tex]
The fourth root of 9 multiplied by square root of 9 over the fourth root of 9 to the power of 5 is:
[tex] \frac{9^{ \frac{1}{4} }*9^{ \frac{1}{2} }}{9^{ \frac{5}{4} }} = \frac{ 9^{ \frac{1}{4}+ \frac{1}{2}} }{9 \frac{5}{4} } =9^{ \frac{1}{4}+ \frac{1}{2}- \frac{5}{4} }=9^{ \frac{1}{4}+ \frac{1*2}{2*2}- \frac{5}{4} }=9^{ \frac{1}{4}+ \frac{2}{4}- \frac{5}{4} }=9^{ \frac{1+2-5}{4} }= 9^{ \frac{-2}{4} }[/tex] [tex]= 9^{- \frac{1}{2} }= \frac{1}{9^{ \frac{1}{2} } } =\frac{1}{ \sqrt[2]{9^{1} } } = \frac{1}{ \sqrt[2]{9} } = \frac{1}{3} [/tex]
To calculate this will use several rules:
[tex] \sqrt[n]{x^m } = x^{ \frac{m}{n} } [/tex]
[tex]x^{-m}= \frac{1}{ x^{m} } [/tex]
[tex] x^{a} * x^{b} =x ^{a+b} [/tex]
[tex] \frac{ x^{a} }{ x^{b} } = x^{a-b} [/tex]
The fourth root of 9 is [tex] \sqrt[4]{9}= \sqrt[4]{ 9^{1} }= 9^{ \frac{1}{4} } [/tex]
Square root of 9 is [tex] \sqrt[2]{9}= \sqrt[2]{ 9^{1} } = 9^{ \frac{1}{2} } [/tex]
The fourth root of 9 to the power of 5 is [tex] \sqrt[4]{9^{5} } = 9^{ \frac{5}{4} } [/tex]
The fourth root of 9 multiplied by square root of 9 over the fourth root of 9 to the power of 5 is:
[tex] \frac{9^{ \frac{1}{4} }*9^{ \frac{1}{2} }}{9^{ \frac{5}{4} }} = \frac{ 9^{ \frac{1}{4}+ \frac{1}{2}} }{9 \frac{5}{4} } =9^{ \frac{1}{4}+ \frac{1}{2}- \frac{5}{4} }=9^{ \frac{1}{4}+ \frac{1*2}{2*2}- \frac{5}{4} }=9^{ \frac{1}{4}+ \frac{2}{4}- \frac{5}{4} }=9^{ \frac{1+2-5}{4} }= 9^{ \frac{-2}{4} }[/tex] [tex]= 9^{- \frac{1}{2} }= \frac{1}{9^{ \frac{1}{2} } } =\frac{1}{ \sqrt[2]{9^{1} } } = \frac{1}{ \sqrt[2]{9} } = \frac{1}{3} [/tex]
(1) Fourth root of 9 multiplied by square root of 9 over the fourth root of 9 to the power of 5.= 9^(1/4) * 9^(1/2) / (9^(1/4))^5, cancel 9^(1/4)= 9^(1/2) / (9^(1/4))^4= 9^(1/2) / 9= 3 / 9= 1/3
(2) Five to the power of negative 1 over 6= 5 ^ (-1/6)= (1/5)^(1/6)
(3) Five to the power of 3 over 2= 5 ^ (3/2)= sqrt(125)
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(2) Five to the power of negative 1 over 6= 5 ^ (-1/6)= (1/5)^(1/6)
(3) Five to the power of 3 over 2= 5 ^ (3/2)= sqrt(125)
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
