Respuesta :

JcAlmighty
y = 2(x - 4)(x + 3)
Let's first multiply factors:
y =2(x · x + x · 3 - 4 · x - 4 · 3)
y = 2(x² + 3x - 4x - 12)
y = 2(x² - x - 12)
Let's multiply 2 with inside the bracket:
y = 2 · x² - 2 · x - 2 · 12
y = 2x² - 2x - 24
taskmasters
The equation given above is a quadratic equation which has a standard form of:

y = ax^2 + bx + c

We write the given equation to that form. We do it as follows:

y=2(x-4)(x+3)
y = 2 (x^2 + 3x - 4x -12)
y = 2(x^2 - x -12)
y = 2x^2 -2x -24

Hope this answers the question. Have a nice day.

Otras preguntas

Q&A Education