An object is hanging by a string from your rearview mirror. While you are decelerating at a constant rate from 25 m/s to rest in 6.0 s, (a) what angle does the string make with the vertical, and (b) is it toward the windshield or away from it?

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04-11-2016
Mathematics

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An object is hanging by a string from your rearview mirror. While you are decelerating at a constant rate from 25 m/s to rest in 6.0 s, (a) what angle does the string make with the vertical, and (b) is it toward the windshield or away from it?

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Аноним Аноним · Answer 1 · 2016-11-10T08:33:53+01:00

The rate of deceleration is equal to 25 m/s / 6 s = 25/6 m/s^2.

(a) The string should be angled in such a way that the horizontal acceleration is equal to 25.6 and the vertical acceleration is equal to gravitational acceleration. Using trigonometry,Angle from the vertical = arctan(25/6 / 9.8) = 23.03 degrees.

(b) Since the car is decelerating, one end of the string attached to the car is pulled back and because of the inertia of the object it is goes on the opposite direction and so the object moves toward the windshield.

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