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An engineer on the ground is looking at the top of a building. The angle of elevation to the top of the building is 46Á. The engineer knows the building is 250 ft tall. What is the distance from the engineer to the base of the building to the nearest whole foot?

Respuesta :

The horizontal distance, height of the building, and the line of sight are the sides of a right triangle. The horizontal distance can be computed using tangents.

 h = y / tan(angle)h = 250 / tan(46 deg)h = 241 ft.


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scme1702
The engineer's distance from the building, the building's height and the engineer's line of sight form a right angle triangle.
Thus, we apply:
tan∅ = height/base
base = 250/tan(46)
base = 241.4 feet
So 241 feet

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