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Look at the triangle.

A right angle triangle is shown with hypotenuse equal to 17 centimeters. An acute angle of the triangle is labeled as xÁ. The side adjacent to the acute angle has length 15 centimeters and the side opposite to the acute angle has length 8 centimeters.

What is the value of cos xÁ? Can someone Explain to me how to solve cos I know it is adj/hyp

Respuesta :

SJ2006

Well, you know Cos I = Adjacent / Hypotenuse

Here, Adjacent = 15 cm &

Hypotenuse = 17 cm

Now, substitute for that,

Cos I = 15/17

Answer:

[tex]cos A = \frac{15}{17}[/tex]

Step-by-step explanation:

Since, In a right triangle,

If [tex]\theta[/tex] is an acute angle,

Then,

[tex]cos \theta = \frac{B}{H}[/tex]

Where, B is the adjacent side of [tex]\theta[/tex] ( Except hypotenuse ),

And, H is the hypotenuse of the triangle,

Here, [tex]\theta = A[/tex],

Hypotenuse of the triangle, H = 17 cm,

While, the adjacent side of angle A, B = 15 cm,

Thus,

[tex]cos A = \frac{15}{17}[/tex]

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