dy/dx = 2xy
dy/y = (2x)dx
INT(1/y)dy = INT(2x)dx
ln y + c = x^2 + d
ln y = x^2 + constant
y = e^(x^2 + constant)
1 = e^constant ... so constant=0 ... so y = e^(x^2)
Verification:
y = e^(x^2)
dy/dx = 2x*e^(x^2) = 2xy
and e^(0^2) = e^0 = 1
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