Respuesta :
parabola vertex form
y= a(x-h)^2 + k => symmetry: x = h
or x = a(y-k)^2 + h => symmetry: y = k
(h,k) => vertex
a = 1/4c
c : distance between vertex and focus or directrix.
.........................................
x^2 – 6x – 8y + 49 = 0
8y = x^2 - 6x + 49 = (x-3)^2-9+49 = (x-3)^2 + 40
y= 1/8 (x-3)^2 + 5
a = 1/8 = 1/4c
c = 2
vertex: (3, 5)
focus: (3, 7)
directrix: y = 3
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y= a(x-h)^2 + k => symmetry: x = h
or x = a(y-k)^2 + h => symmetry: y = k
(h,k) => vertex
a = 1/4c
c : distance between vertex and focus or directrix.
.........................................
x^2 – 6x – 8y + 49 = 0
8y = x^2 - 6x + 49 = (x-3)^2-9+49 = (x-3)^2 + 40
y= 1/8 (x-3)^2 + 5
a = 1/8 = 1/4c
c = 2
vertex: (3, 5)
focus: (3, 7)
directrix: y = 3
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!