Respuesta :

Molar mass NH3 = 17.031 g/mol

1 mole NH3 ---------- 17.031 g
?? moles -------------- 1.2x10³ g

moles NH3 =  1 x ( 1.2x10³  ) / 17.031

moles NH3 = 1.2x10³ / 17.031

= 70.45 moles of NH3

hope this helps!

Answer : The number of moles present in ammonia is, 70.459 moles.

Solution : Given,

Mass of ammonia = [tex]1.2\times 10^3g[/tex]

Molar mass of ammonia = 17.031 g/mole

Formula used :

[tex]\text{Moles of }NH_3=\frac{\text{ given mass of }NH_3}{\text{ molar mass of }NH_3}[/tex]

[tex]\text{Moles of }NH_3=\frac{1.2\times 10^3g}{17.031g/mole}=70.459moles[/tex]

Therefore, the number of moles present in ammonia is, 70.459 moles.

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