Answer:
36.43m
Step-by-step explanation:
Let the wingspan of the real aeroplane = x
The scale of the model is 4 cm to 15 m.
= 4: 15 = 4/15.
Sunita's model has a wingspan of 17cm.
Hence:
4cm/15m = 17cm/xm
Cross Multiply
4x = 15 × 17
4x = 255
x = 255/4
x = 36.428571429 m
Approximately = 36.43 m
Therefore, the wingspan of the real aeroplane is 36.43m
