Respuesta :
Answer:
 μ = 0.66,   therefore if it compiesy with the regulations
Explanation:
Let's solve this exercise in part, let's start by finding with kinematics the acceleration of man
      y = v₀ t + ½ a t²
as it starts from rest the initial velocity is zero
     y = ½ a t²
     a = [tex]\frac{2y}{t^2}[/tex]
     a =\frac{2 \ 4.38}{1.21^2} Â
     a = 6.46 m / s²
Now let's use Newton's second law,
Axis y
     N- W = 0
     N = W
     N = m g
X axis
on this axis the man exerts a backward force and by the law of action and reaction the floor exerts a forward force of the same magnitude, this forward force is the friction force.
     fr = m a
  Â
the friction force has an expression
     fr = my N
let's substitute
   μ mg = m a
   μ = a / g
 Â
let's calculate
   μ = 6.46 / 9.8
   μ = 0.66
therefore if you comply with the regulations