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PLEASE HELPPP!!! Calculate the mass (in grams) of lithium hydroxide that would be needed to produce 8.03 mol of
lithium sulfate in the reaction below.
2 LIOH + H2S04 -> Li2SO4 + 2 H20

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FloridianEmpire

Answer:

385g LiOH

Explanation:

Assuming the equation is balanced...

(8.03 mol Li2SO4) x (2 LiOH/ 1 Li2SO4)

= 16.1 mol LiOH ;

16.1 mol LiOH x (24g LiOH/ 1 mole LiOH) = 385g LiOH

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