Answer:
2.72*10-3 Joules
Explanation:
From Newton's second law of motion
F=ma
[tex]\tau=I*\alpha[/tex]
given
[tex]\tau= 0.11Nm\\\\I=0.034kgm^2\\\\t= 8s\\\\\alpha=?[/tex]
[tex]\alpha =0.11/0.034\\\\\alpha=3.23 rad/s^2[/tex]
the angular velocity is
[tex]\omega = \alpha/t\\\\\omega =3.23/8\\\\\omega =0.4 rad/s[/tex]
[tex]KE= 1/2*I* \omega^2[/tex]
[tex]KE=1/2*0.034*0.4^2\\\\KE=1/2*0.034*0.16\\\\KE=0.00272\\\\KE=2.72*10^-3J[/tex]
