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A sample of argon, Ar, has a volume of 5.40 L with an unknown pressure. The gas has a volume of 9.73 L when the pressure is 3.62 atm,
with no change in temperature and amount of gas. What was the initial pressue in atm of the gas?
O a. 6.523 atm
O b. 6.52 atm
Oc 2.009 atm
Od. 2,01 atm

Respuesta :

Stephen46

Answer:

6.52 atm

Explanation:

The initial pressure can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we are finding the initial pressure

[tex]P_1 = \frac{P_2V_2}{V_1} \\[/tex]

From the question we have

[tex]P_1 = \frac{9.73 \times 3.62}{5.40} = \frac{35.2226}{5.40} \\ =6.522703...[/tex]

We have the final answer as

6.52 atm

Hope this helps you

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