Explanation:
The pH of a solution can you be found by using the formula
[tex]pH = - log [ { H_3O}^{+}][/tex]
Since we are finding the [H3O+] , substitute the value of the pH and find it's antilog
We have
[tex]4.63 = - log[ { H_3O}^{+}] \\ [ { H_3O}^{+}] = {10}^{ - 4.63} \\ \\ = 2.344 \times {10}^{ - 5} mol {dm}^{ - 3} [/tex]
Hope this helps you
