Answer:
0.416 mol CaBr₂
General Formulas and Concepts:
Chemistry - Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
Step 1: Define
83.1 g CaBr₂
Step 2: Identify Conversions
Molar Mass of Ca - 40.08 g/mol
Molar mass of Br - 79.90 g/mol
Molar Mass of CaBr₂ - 40.08 + 2(79.90) = 199.88 g/mol
Step 3: Convert
[tex]83.1 \ g \ CaBr_2(\frac{1 \ mol \ CaBr_2}{199.88 \ g \ CaBr_2} )[/tex] = 0.415749 mol CaBr₂
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
0.415749 mol CaBr₂ ≈ 0.416 mol CaBr₂
