Answer:
[tex]\overline{ \underline{\boxed{b = \frac{(9 - 2a)}{6} }}}[/tex]
Step-by-step explanation:
[tex]if \: a \: \overline{ \underline{ \boxed{ \infty }}} \: b= \frac{2}{a} ( \frac{3}{2} - b) = - \frac{2}{3} \\ \\ \frac{6}{2a} - \frac{2b}{a} = - \frac{2}{3} \\ \\ 6(3) - 2b(6) = 2(2a) \\ 18 - 12b = 4a \\ 12b = 18 - 4a \\ b = \frac{18 - 4a}{12} \\ \overline{ \underline{\boxed{b = \frac{(9 - 2a)}{6} }}}[/tex]
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