cmon pls helppp im asking so many times please help
Answer:
a) [tex]\huge\boxed{\sf Area\ of\ Parallelogram = 6\ ft.\²}[/tex]
b) [tex]\huge\boxed{\sf Area\ of\ the\ equal\ triangles = 3\ ft.\²}[/tex]
Step-by-step explanation:
Part A:
Area of Parallelogram = Base * Height
Where Base = 8 ft. and Height = 3/4 ft.
Area of Parallelogram = 8 * 3/4
Area of Parallelogram = 2 * 3
Area of Parallelogram = 6 ft.²
[tex]\rule[225]{225}{2}[/tex]
Part B:
We can divide the parallelogram into two equal triangles by drawing a diagonal AC or BD. This would create two congruent triangles having an equal area.
Area of the equal triangles = Area of parallelogram / 2
Area of the equal triangles = 6 / 2
Area of the equal triangles = 3 ft.²
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!