Answer:
x ≤ - 2 or x ≥ 4
Step-by-step explanation:
Inequalities of the type | x | ≥ a always have solutions in the form
x ≤ - a or x ≥ a
Thus for the given inequality
[tex]\frac{3x-3}{9}[/tex] ≤ - 1 or [tex]\frac{3x-3}{9}[/tex] ≥ 1
Solving each inequality
[tex]\frac{3x-3}{9}[/tex] ≤ - 1 ( multiply both sides by 9 )
3x - 3 ≤ - 9 ( add 3 to both sides )
3x ≤ - 6 ( divide both sides by 3 )
x ≤ - 2
or
[tex]\frac{3x-3}{9}[/tex] ≥ 1 ( multiply both sides by 9 )
3x - 3 ≥ 9 ( add 3 to both sides )
3x ≥ 12 ( divide both sides by 3 )
x ≥ 4
Solution is x ≤ - 2 or x ≥ 4
