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The circuit diagram shows three resistors connected in series across a 6.0V supply.
6.0V
+
3.092
4.092
5.012
What is the potential difference (p.d.) across the 4.0 12 resistor?
A) 0.67 V
B) 1.5 V
C) 2.0 V
D) 6.0V
​

The circuit diagram shows three resistors connected in series across a 60V supply60V309240925012What is the potential difference pd across the 40 12 resistorA 0 class=

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Luciiferr

Answer:

the correct answer is option C , 2.0 V( volts ) !!

explanation : Total potential difference = 6 V

Total resistance = ( 3 + 4 + 5 ) ohms = 12 ohms

so , applying ohm's law to the whole circuit , we get :

V/ I = R

6/ I = 12

I = 6/ 12 = 1/2 = 0.5 ( total current ) ampere or A

now Current through 4 Ohms Resistance = 0.5 A

Resistance we know= 4 Ohms

Applying ohm's law :

V/I = R

V/0.5 = 4

V = 0.5 × 4 = 2 V

kapoorprachi783

The potential difference (p.d.) across the resistor is 2.0 V.

How to find the potential difference (p.d.) across the resistor?

The individual voltage drops across each resistor can be simply calculated as V = I*R where R represents the resistance value.

Total potential difference = 6 V

Total resistance = ( 3 + 4 + 5 ) ohms = 12 ohms

so, applying ohm's law to the whole circuit, we get :

V/ I = R

6/ I = 12

I = 6/ 12 = 1/2 = 0.5 ( total current ) ampere or A

Now Current through 4 Ohms Resistance = 0.5 A

The resistance we know= 4 Ohms

Applying ohm's law :

V/I = R

V/0.5 = 4

V = 0.5 × 4 = 2 V

Ohm's law states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperatures remain constant.

Learn more about the potential differences here: brainly.com/question/24119414

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