Answer:
The solution of the system of equations is (-8,3).
Step-by-step explanation:
Given that:
3x + y = -21 Eqn 1
x + y = -5 Eqn 2
First of all, we will subtract Eqn 2 from Eqn 1
(3x+y)-(x+y)=-21-(-5)
3x+y-x-y=-21+5
2x=-16
Dividing both sides by 2
[tex]\frac{2x}{2}=\frac{-16}{2}[/tex]
x=-8
Putting the value x=-8 in Eqn 2
-8+y= -5
Adding 8 on both sides
-8+8+y= -5+8
y=3
Hence,
The solution of the system of equations is (-8,3).
