Answer:
V = 268.8 L
Explanation:
Given data:
Number of moles of nitrogen = 12 mol
Temperature = 273 K
Pressure = 1atm
Volume occupy = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
1 atm × V = 12 mol ×0.0821 atm.L/ mol.K × 273 K
V = 268.95 atm.L / 1 atm
V = 268.8 L
