Respuesta :

nadia2318116

Answer:

Step-by-step explanation:

Say that :

a=6   ,  b=6[tex]\sqrt{3}[/tex]

and the diagonal is c=?

c^2=a^2+b^2

So

c[tex]\sqrt{a^{2}+b^{2} } =\sqrt{6^{2}+(6\sqrt{3})^{2} } \\=12[/tex]

I hope it will help you :)

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