If two individuals heterozygous for freckles have a child, the probability that the child will have freckles is ¾.
- According to this question, a gene coding for the possession or not of freckles is involved. The allele for freckles (F) is dominant over the allele for no freckles (f).
- If two individuals that are heterozygous for freckles are crossed i.e. Ff × Ff, the following gametes will be produced by each parent: F and f.
- Using these gametes in a punnet square, the following offsprings will be produced: FF, Ff, Ff, and ff.
- FF (1) - possess freckles
- Ff (2) - possess freckles
- ff (1) - no freckles
- Since ¾ of the offsprings have freckles, hence, ¾ × 100 = 75% of the offsprings in this cross will have freckles.
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