Answer:
y = 4[tex]\sqrt{3}[/tex]
Step-by-step explanation:
Using the altitude- on- hypotenuse theorem
( leg of large Δ )² = ( part of hypotenuse below it ) × ( whole hypotenuse )
y² = 6 × (6 + 2) = 6 × 8 = 48 ( take the square root of both sides )
y = [tex]\sqrt{48}[/tex]
= [tex]\sqrt{16(3)}[/tex] = [tex]\sqrt{16}[/tex] × [tex]\sqrt{3}[/tex] = 4[tex]\sqrt{3}[/tex]
