The energy stored will be "4 J".
Given:
- Force, F = 20 N
- Spring constant, k = 50 N/m
By using the Hooke's law states,
→ [tex]F = -kx[/tex]
By substituting the values, we get
→ [tex]20= -(50) x[/tex]
[tex]x = -\frac{20}{50}[/tex]
[tex]= -\frac{2}{5}[/tex]
hence,
The energy will be:
= [tex]\frac{1}{2} kx^2[/tex]
By putting the values,
= [tex]\frac{1}{2}\times 50\times (\frac{2}{5} )^2[/tex]
= [tex]4 \ J[/tex]
Thus the above answer is right.
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