The equation modeling the population growth of a small town is P(t)=30000(1.02)^t, where P represents the population, and t represents the years from now. What is the approximate population change that occurs between 2 years from now and 10 years from now.
a.5,358
b.6,570
c.31,212
d.35,150
e.36,570

Respuesta :

Answer: I’m not for sure but I got 31,212

Step-by-step explanation: You multiply 30000 to 1.02 and then with the 2 and the 10 you divided and get 31,212

The population change between these years is (a) 5358

The population model is given as:

[tex]\mathbf{P(t) = 30000(1.02)^t}[/tex]

When t = 2, we have:

[tex]\mathbf{P(2) = 30000(1.02)^2}[/tex]

[tex]\mathbf{P(2) = 31212}[/tex]

When t = 10, we have:

[tex]\mathbf{P(10) = 30000(1.02)^{10}}[/tex]

[tex]\mathbf{P(10) = 36570}[/tex]

The population change is then calculated as:

[tex]\mathbf{\Delta P = P(10) - P(2)}[/tex]

So, we have:

[tex]\mathbf{\Delta P = 36570 - 31212}[/tex]

[tex]\mathbf{\Delta P = 5358}[/tex]

Hence, the population change between these years is (a) 5358

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