Respuesta :

kk5996282

Answer:

Explanation:

mass of 5 mole of oxygen=5*32=160 g

mass of propane =39 g

39 g of propane  burn in 160 g of oxygen

so x g could burn in 48.0 g of oxygen=x*160=39*48.0

x=1872/160=11.7 g

therefore 11.7 g of propane could burn in 48.0 g of oxygen

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