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Problem 1: Triple + Double = So Much Trouble

Write a program that reads two integers, checks if a digit repeats 3 times in a row in the first integer and that same digit repeats two times in a row in the second integer.


Sample input/output:

Enter two integers: 3555761 72559

There are 3 conservative digits 5 in 3555761 and 2 in 72559

Respuesta :

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Answer:

Explanation:

The program code is written as:

#include <iostream>

using namespace std;

 

int main() {

    int num1,num2,flag=0,flag1=0,flag_val=0,temp1,temp2,f1,f2,f3,m1,m2;

    cout<<"Enter First Number ";

    cin>>num1;

    cout<<"Enter Second Number ";

    cin>>num2;

    temp1=num1;

    temp2=num2;

    while(temp1>0)

    {

    f1=temp1%10;

temp1=temp1/10;

    f2=temp1%10;

    if(f1!=f2)

       continue;

    temp1=temp1/10;

    f3=temp1%10;

       if(f1==f2 && f2==f3)

       {

       flag=1;

       flag_val=f1;

       }

    }

    while(temp2>0)

    {

    m1=temp2%10;

    temp2=temp2/10;

    m2=temp2%10;

    if (m1!=m2)

       continue;

    temp2=temp2/10;

    if(m1==m2 && flag==1 && flag_val==m1)

    {

       flag1=1;

       break;

    }

   

    }

    if (flag1==1)

    {

    cout<<"Both Number Are Triple + Double";

    }

    else

    {

    cout<<"Both number Are not Triple +Double";

    }

 

return 0;

}

OUTPUT:

Enter First Number = 3555761

Enter Second Number = 72559

Both numbers are Triple + DoublePress any key to continue .....

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