Complete Question
The complete question is shown on the first uploaded image
Answer:
The mass of the other block is [tex]m_1 = 81.14 \ kg[/tex]
Explanation:
From the question we are told that
Mass of the first block is [tex]m_1 = 100 \ kg[/tex]
The height is [tex]s = 1.0 \ m[/tex]
The time it takes it is [tex]t = 1.40 \ s[/tex]
Generally from kinematic equation
[tex]s = ut + \frac{1}{2} at^2[/tex]
Here u is the initial velocity which zero given that it was at rest initially
So
[tex]s = 0 * t + \frac{1}{2} at^2[/tex]
=> [tex]s = \frac{1}{2} at^2[/tex]
=> [tex]1 = \frac{1}{2}* a * (1.40 )^2[/tex]
=> [tex]a = 1.0204 \ m/s^2[/tex]
Generally from the diagram the resultant force due to the weight of the first object and the tension on the string is mathematically represented as
[tex]mg - T = ma[/tex]
=> [tex]T = m g - ma[/tex]
=> [tex]T = m(g - a)[/tex]
=> [tex]T = 877.96 \ N[/tex]
Generally from the diagram the resultant force due to the weight of the second object and the tension on the string is mathematically represented as
[tex]T - m_1g = m_1 a[/tex]
=> [tex]877.96 = m_1 (a + g)[/tex]
=> [tex]877.96 = m_1 (1.0204 + 9.8 )[/tex]
=> [tex]m_1 = 81.14 \ kg[/tex]
