Answer:
edge length a = 636.7 pm
Explanation:
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The edge length (in pm) of the hypothetical metal genchemium is;
a = 0.6367 pm
We are given;
Atomic mass; M = 150 g/mol
Density; ρ = 1.96 g/cm³
This is a BCC structure and as such formula to find the edge length is;
ρ = (z × M)/(N × a³)
where;
z = number of atoms available in each unit cell = 2 atoms
M is atomic mass
N is avogadro's number = 6.023 × 10²³ mols
a is edge length
Thus, making a the subject gives;
a = ∛(z × M)/(N × ρ)
Plugging in the relevant values;
a = ∛(2 × 150)/(6.023 × 10²³ × 1.96)
a = 63.67 × 10⁻⁹ cm
converting to meters gives;
a = 0.6367 × 10⁻⁹ m
converting to pm gives;
a = 0.6367 pm
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