The components of vectors A and B are given as follows:

Ax = 7.6

Bx = -5.1

Ay = -9.2

By = -6.8

What is the magnitude of the vector difference B - À?

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hamzaahmeds hamzaahmeds · Answer 1 · 2020-12-05T01:45:26+01:00

Answer:

|B - A| = 12.92 units

Explanation:

In order to find the magnitude of B-A vector, we first write A and B in Vector Notation:

A = Aₓ i + Ay j

A = 7.6 i - 9.2 j

B = Bₓ i + By j

B = -5.1 i - 6.8 j

So, there difference will be:

B - A = (-5.1 i - 6.8 j) - (7.6 i - 9.2 j)

B - A = -12.7 i + 2.4 j

Now, the magnitude of this vector can be found out by using the formula:

|B - A| = √[(x-component)² + (y-component)²]

|B - A| = √[(-12.7)² + (2.4)²]

|B - A| = 12.92 units

facundo3141592 facundo3141592 · Answer 2 · 2022-01-27T13:17:50+01:00

We will see that the magnitude of the difference of the vectors is 12.92

Here we have two vectors:

A = <7.6, -9.2>

B = <-5.1, -6.8>

To get the difference we just subtract the correspondent components:

B - A = <Bx - Ax, By - Ay> = <-5.1 - 7.6, -6.8 - (-9.2)> = <-12.7, 2.4>

The magnitude of that vector is just:

[tex]M = \sqrt{(2.4)^2 + (-12.7)^2} = 12.92[/tex]

If you want to learn more about vectors, you can read:

https://brainly.com/question/4889980