Answer:
D. the same as force. the applied force per cross-sectional area.
Explanation:
Tensile stress of a material is defined as the ratio of the applied force on the material to its cross sectional area. this is expressed mathematically as;
Tensile stress = Force/cross sectional area
Tensile stress = F/A
Force is measured in newton while cross sectional area is measured in m
Hence the unit of Tensile stress is N/m²
The tensile stress is the same as force. the applied force per cross-sectional area. Hence, option (D) is correct .
The given problem is based on the concept of stress and strain. The force applied on a material per unit area is known as Stress. It is denoted by the symbol [tex]\sigma[/tex] .
And due to the applied force, the ratio of change in length to the original length is known as Strain. It is denoted by the symbol [tex]\epsilon[/tex].
And the ratio of Stress and Strain is known as Elastic modulus. That is,
[tex]E = \dfrac{stress}{strain}\\\\E = \dfrac{\sigma }{\epsilon}[/tex]
So, the tensile stress is obtained as,
[tex]E = \dfrac{\sigma}{\epsilon}\\\\\sigma = E \times \epsilon[/tex]
So, clearly stress is nothing but the force applied per unit cross sectional area. That is,
[tex]\sigma = \dfrac{F}{A}[/tex]
Thus, we can conclude that the tensile stress is the same as force. the applied force per cross-sectional area. Hence, option (D) is correct .
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