Suppose IQ scores were obtained for 20 randomly selected sets of twins. The 20 pairs of measurements yield x overbarequals103.26​, y overbarequals102.05​, requals0.897​, ​P-valueequals​0.000, and ModifyingAbove y with caret equals negative 13.47 plus 1.12 x​, where x represents the IQ score of the twin born first. Find the best predicted value of ModifyingAbove y with caret given that the twin born first has an IQ of 105​? Use a significance level of 0.05.

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Answer

The  value is  [tex]P = 131.07[/tex]

Step -by -step -explanation :

 From the question we are old that

         The sample size is  n =  20  

         The sample mean for the first person of each twin is  [tex]\= x = 100.45[/tex]

         The sample mean for the second person of each twin is  [tex]\= y = 103[/tex]

          The  correlation between both data is  r =  0.908

         The p-value is  p-value  =  0.000

          The  equation  [tex]\^ y = 13.47 + 1.12 x[/tex]

         

Here we are told that x represents  the first person to be given birth to among each twin  

       The value of x  considered is  x = 105

          Generally given that p-value  =  0.000

Then  the  Predicted value of  [tex]\^ y[/tex]  is mathematically represented as

           [tex]P = 13.47 + 1.12 (105)[/tex]

=>         [tex]P = 131.07[/tex]

           

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