Answer:
3.10 L
Explanation:
A reaction at 11.0°C evolves 133.mmol of boron trifluoride gas. Calculate the volume of boron trifluoride gas that is collected. You can assume the pressure in the room is exactly 1 atm. Round your answer to 3 significant digits.
Step 1: Convert the temperature to the Kelvin scale
When working with gases, we must use the absolute temperature scale. We can convert the temperature from Celsius t Kelvin using the following expression.
K = °C + 273.15
K = 11.0°C + 273.15
K = 284.2 K
Step 2: Convert the amount of matter to moles
We will use the conversion factor 1 mol = 1000 mmol.
133 mmol × (1 mol/1000 mmol) = 0.133 mol
Step 3: Calculate the volume of boron trifluoride gas
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 0.133 mol × (0.0821 atm.L/mol.K) × 284.2 K / 1 atm
V = 3.10 L
